Homework SourseUnder conditions other than standard state the followingequa
Under conditions other than standard state, the followingequation applies:
| Substance | Pressure ( |
| 5.55 | |
| 5.75 | |
| 2.25×102 |
Solution
G = -2.303 RT logKp
The given equation is :
Kp = PC2H6 / PH22 PC2H2
= 2.25 x 10-2 / 5.55 x ( 5.75 )2
= 1.226 x 10-4
We Know that :
G = R T ln Kp
= 8.314 J / mol- K/ 1000 x 373 K x log (1.226 x 10-4 )
= -27.93051 KJ
Grxn. = G0 + RT lnKp
= -242.1 Kj + ( -27.93051 ) KJ
= -270.03KJ
Kp = PC2H6 / PH22 PC2H2
= 2.25 x 10-2 / 5.55 x ( 5.75 )2
= 1.226 x 10-4
We Know that :
G = R T ln Kp
= 8.314 J / mol- K/ 1000 x 373 K x log (1.226 x 10-4 )
= -27.93051 KJ
Grxn. = G0 + RT lnKp
= -242.1 Kj + ( -27.93051 ) KJ
= -270.03KJ
We Know that :
G = R T ln Kp
= 8.314 J / mol- K/ 1000 x 373 K x log (1.226 x 10-4 )
= -27.93051 KJ
Grxn. = G0 + RT lnKp
= -242.1 Kj + ( -27.93051 ) KJ
= -270.03KJ
